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Java Runtime.Exec Can't Find Batch File Unless It Exists In PathJava Runtime.exec is not the easiest method to use. In fact, it's much harder to use than any exec commands I have ever seen. I don't know if it is the heightened security features or what, but it really doesn't make life easy. Today, I've been trying to execute a batch file using it by passing the batch file as a command and then setting the batch file's directory as the working directory. But I gget the following error message: java.io.IOException: Cannot run program "Launcher.bat" (in directory "C:\transfer\briefcase\Cyrah Tasks\Prototype Launcher Task"): CreateProcess error=2, The system cannot find the file specified The thing is, "Launcher.bat" is really in that directory. On the other hand, if I change "Launcher.bat" to "Prototype.bat", then this IOException doesn't occur. After banging my head on the table for a long time, I finally figured out that I have a DIFFERENT "Prototype.bat" in the "path" environment variable. Java must have checked the path, found that one, and executed the current one in the working directory. What a strange way Java executes external programs? Chieh Cheng
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